use of ai for solving my approach in java

 class Main {

    public static void main(String[] args) {

       int [] arr={1,2,3,4,4,5,5,5};

      // because one element is already present

       int [] freq=new int [arr.length];

       boolean [] visit=new boolean[arr.length];

       int index=0;

       //finding elemets with their frequency:

       for(int i=0;i<arr.length;i++){

              if(visit[i]){

                  continue;

              }

               int count=1;

           for(int j=i+1;j<arr.length;j++){

               if(arr[i]==arr[j]){

                   visit[j]=true;

                   count++;


               }

               freq[i]=count;

           }

       

              // System.out.println(arr[i]+":"+freq[i]);

       }

       //finding maximum frequency:

        int max=Integer.MIN_VALUE;

       for(int i=0;i<freq.length;i++){

            //System.out.println(freq[i]);

            if(freq[i]>max){

                max=freq[i];

            }

       }

       //finding element with huge frequency

       for(int i=0;i<freq.length;i++){

           if(!visit[i] && freq[i]==max){

               System.out.println(arr[i]);

           }

       }

    }

}

//usage of for loop with huge frequency:

    • i = 0: !visit[0] is true, freq[0] = 1 ≠ 3 → skip
    • i = 1: same → skip
    • i = 2: same → skip
    • i = 3: freq[3] = 2 ≠ 3 → skip
    • i = 4: visit[4] = true → skip
    • i = 5: !visit[5] = true, freq[5] = 3 == max → ✅ print arr[5] = 5
    • i = 6, 7: visit = true → skip

    ✅ Final Output: 5

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